2500x^2-100x-15=0

Solution for 2500x^2-100x-15=0 equation:

2500x^2-100x-15=0

a = 2500; b = -100; c = -15;
Δ = b2-4ac
Δ = -1002-4·2500·(-15)
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{160000}=400$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-400}{2*2500}=\frac{-300}{5000}
=-3/50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+400}{2*2500}=\frac{500}{5000}
=1/10
$